5v^2-4v-105=0

Solution for 5v^2-4v-105=0 equation:

5v^2-4v-105=0

a = 5; b = -4; c = -105;
Δ = b2-4ac
Δ = -42-4·5·(-105)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-46}{2*5}=\frac{-42}{10}
=-4+1/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+46}{2*5}=\frac{50}{10}
=5
$